Question

Potassium metal reacts with water according to the balanced equation shown: 2 K + 2 H202 KOHH a. If one mole of potassium reacts in this manner, how many moles of water are consumed? b. If one mole of potassium reacts in this manner, how many moles of H2 will form? c. How many moles of potassium are required to produce 14.0 moles of H2 d. How many moles of KOH would be produced if 3,014.2 moles of H20 are consumed?

Answer 1

2 K + 2 H_2 O rightarrow 2 KOH + H_2 (a) 2 mole K identicalto 2 mole of H_2O So 1 mole K = 1 mole of H_2O will consumed (b) 2 mole K identicalto 1 mole of H_2 So 1 mole K = 0.5 mole of H_2 will form (c) 1 mole H_2 identicalto 2 mole K So 14 mole H_2 = 2 times 14 = 28 mole of K is required \r\n (d) 2 mole H_2O identicalto 2 mole of KOH So 3014.2 moles of H_2O = 2/2 times 3014.2 mole KOH = 3014.2 mole KOH will be produced