Question

Black smokers are found in the depths of the oceans. Thinking that the conditions in these smokers might be conducive to the formation of organic compounds, two chemists in Germany found the following reaction could occur in similar conditions. 2 CH3SH + CO + CH3 COSCH3 + H2S If you begin with 47.1 g of CH3 SH and excess CO, what is the theoretical yield of CH3 COSCH3 ? g CH3 COSCH If you isolate 31.7 g of CH3 COSCH3, what is the percent yield of CH3COSCH3 ?

Answer 1

Step 1: Explanation:

A mole ratio is ​the ratio between the amounts in moles of any two compounds involved in a chemical reaction. The mole ratio can be determined by examining the coefficients in front of formulas in a balanced chemical equation.

Step 2: write the balanced chemical equation.

2CH₃SH  + CO---> CH₃COSCH₃ + H₂S

Step 3: calculate the moles of CH₃SH

we know, moles = mass given / molar mass = ( 47.1 g / 48.11 g/mol ) = 0.979 mol

Step 4: Calculate the moles of carbon dioxide

2CH₃SH  + CO---> CH₃COSCH₃ + H₂S

According to the reaction:
2 mol CH₃SHof produce 1 mol of CH₃COSCH₃
so, 0.979 mol of CH₃SH will produce=( 1 mol of CH₃COSCH₃ / 2 mol of CH₃SH )×0.979 mol of CH₃SH = 0.4895 mol of CH₃COSCH₃

Step 5: Calculation of CH₃COSCH₃ produced

we get moles of CH₃COSCH₃ that can be produced = 0.4895 mol

Mass of CH₃COSCH₃ produced =( moles×molar mass ) = (0.163 mol × 90.1441 g/mol ) = 44.126 g

(B) step 6: Calculation of percent yield of CH₃COSCH₃

Given, actual yield = 31.7 g

We got theoretical yield = 44.1 g

We know, Percent yield = (actual yield / theoretical yield ) × 100 %

Percent yield = (31.7 / 44.126 ) × 100 % = 71.84 %