Homework Answers
Solution
Amount payable annually = $12000
Term (Years) = 4
Interest Rate = 5%
Therefore, Present Value of Annuity of $1 @5% for 4 Years = 3.55
Therefore, Present Value of Annual Payment = $12000 X 3.55
= $42600
Answer: Option (D) $42600
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QUESTION 13 PRESENT VALUE TABLES Table A: PV of $1 (Annuity) Table B: Present Value of...
Question Help The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84...
Question Help The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86 0.79 0.73 0.95 0.73 0.71 0.83 0.82 0.88 0.93 0.91 0.83 (a) Determine the sample standard deviation weight. = __?__ gram (Round to two...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. S= gram (Round to two decimal places as...
I need help with question (d) T 0.82 The following data represent the weights (in grams)...
I need help with question (d)
T 0.82 The following data represent the weights (in grams) of a random sample of 50 candies. 0.89 0.87 0.87 0.84 0.95 0.81 0.94 0.97 0.75 0.76 0.75 0.78 0.84 0.85 0.82 0.92 0.78 0.72 0.83 0.81 0.82 0.82 0.82 0.87 0.81 0.91 0.78 0.81 0.96 0.72 0.86 0.84 0.86 0.94 0.74 0.82 0.87 0.92 0.89 0.86 0.91 0.85 0.84 0.79 0.77 0.81 0.78 0.87 0.74 (a) Determine the sample standard deviation weight. S=...
I need help at the bottom with - (d) Determine the actual percentage of candies that...
I need help at the bottom with - (d) Determine the actual percentage of candies that weigh between 0.7 and 0.98 gram, inclusive - Thank you! The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. s= 0.07 gram (Round to two decimal places...
I need help with the final part - (f) Determine the actual percentage of candies that...
I need help with the final part - (f) Determine the actual percentage of candies that weigh more than 0.91 gram. - Thank you! The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86 0.79 0.73...
The data to the right represent the weights (in grams) of a random sample of 50...
The data to the right represent the weights (in grams) of a random sample of 50 candies. Complete parts (a) through (f). 0.89 0.85 0.91 0.95 0.75 0.85 0.86 0.75 0.82 0.98 0.86 0.79 0.77 0.75 0.71 0.83 0.82 0.92 0.77 0.73 0.82 0.84 0.82 0.83 0.85 0.87 0.81 0.92 0.77 0.82 0.99 0.73 0.89 0.86 0.87 0.83 0.82 0.85 0.87 0.93 0.82 0.74 0.84 0.89 0.93 0.92 0.84 0.77 0.79 0.83 (a) Determine the sample standard deviation weight gram(s)...
i need help with with c and d. im using the T1-84 calculator for my class....
i need help with with c and d. im using the T1-84 calculator
for my class. thank you
X23. The Empirical Rule The following data represent the weights (in grams) of a random sample of 50 M&M plain candies. 0.87 0.88 0.82 0.90 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91 0.86 0.87 0.93 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.91 0.91 0.86 0.89 0.87 0.84 0.88 0.88 0.89 0.79 0.82 0.83 0.90 0.88 0.84...
The following data on interbirth interval (time between births), child survivorship, and percent of children married...
The
following data on interbirth interval (time between births), child
survivorship, and percent of children married were collected to
evaluate reproductive decisions within a population. Assuming a
woman of this population has a 20-year reproductive span (maximum
time available from first to last birth), use these data to 1)
calculate the maximum number of live births a woman could have, and
2) determine the number of births that will lead to the highest
fitness (surviving children who marry) if we...
Please answer each of the parts in the following question. Show all steps. Thanks in advance!...
Please answer each of the parts in the following question. Show
all steps. Thanks in advance!
The following data represent the weights (in grams) of a random sample of 50 candies. 0.86 0.84 0.93 0.99 0.73 0.85 0.87 0.77 0.82 0.83 0.82 0.78 0.76 10.75 0.75 0.84 0.86 0.93 0.77 0.74 0.83 0.99 0.83 0.83 0.85 0.86 0.81 0.95 0.79 0.83 0.96 0.75 0.88 0.86 0.88 0.85 0.82 0.87 0.86 0.91 0.87 0.74 0.83 0.85 0.93 0.87 0.84 0.74 0.77...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. S= gram (Round to two decimal places as...
I need help with question (d)
T 0.82 The following data represent the weights (in grams) of a random sample of 50 candies. 0.89 0.87 0.87 0.84 0.95 0.81 0.94 0.97 0.75 0.76 0.75 0.78 0.84 0.85 0.82 0.92 0.78 0.72 0.83 0.81 0.82 0.82 0.82 0.87 0.81 0.91 0.78 0.81 0.96 0.72 0.86 0.84 0.86 0.94 0.74 0.82 0.87 0.92 0.89 0.86 0.91 0.85 0.84 0.79 0.77 0.81 0.78 0.87 0.74 (a) Determine the sample standard deviation weight. S=...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. s= 0.07 gram (Round to two decimal places...
The data to the right represent the weights (in grams) of a random sample of 50 candies. Complete parts (a) through (f). 0.89 0.85 0.91 0.95 0.75 0.85 0.86 0.75 0.82 0.98 0.86 0.79 0.77 0.75 0.71 0.83 0.82 0.92 0.77 0.73 0.82 0.84 0.82 0.83 0.85 0.87 0.81 0.92 0.77 0.82 0.99 0.73 0.89 0.86 0.87 0.83 0.82 0.85 0.87 0.93 0.82 0.74 0.84 0.89 0.93 0.92 0.84 0.77 0.79 0.83 (a) Determine the sample standard deviation weight gram(s)...
i need help with with c and d. im using the T1-84 calculator
for my class. thank you
X23. The Empirical Rule The following data represent the weights (in grams) of a random sample of 50 M&M plain candies. 0.87 0.88 0.82 0.90 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91 0.86 0.87 0.93 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.91 0.91 0.86 0.89 0.87 0.84 0.88 0.88 0.89 0.79 0.82 0.83 0.90 0.88 0.84...
The
following data on interbirth interval (time between births), child
survivorship, and percent of children married were collected to
evaluate reproductive decisions within a population. Assuming a
woman of this population has a 20-year reproductive span (maximum
time available from first to last birth), use these data to 1)
calculate the maximum number of live births a woman could have, and
2) determine the number of births that will lead to the highest
fitness (surviving children who marry) if we...
Please answer each of the parts in the following question. Show
all steps. Thanks in advance!
The following data represent the weights (in grams) of a random sample of 50 candies. 0.86 0.84 0.93 0.99 0.73 0.85 0.87 0.77 0.82 0.83 0.82 0.78 0.76 10.75 0.75 0.84 0.86 0.93 0.77 0.74 0.83 0.99 0.83 0.83 0.85 0.86 0.81 0.95 0.79 0.83 0.96 0.75 0.88 0.86 0.88 0.85 0.82 0.87 0.86 0.91 0.87 0.74 0.83 0.85 0.93 0.87 0.84 0.74 0.77...
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