I need help with the final part - (f) Determine the actual percentage of candies that...
I need help with the final part - (f) Determine the actual percentage of candies that weigh more than 0.91 gram. - Thank you!
The following data represent the weights (in grams) of a random sample of 50 candies.
0.85
0.89
0.82
0.81
0.85
0.87
0.96
0.89
0.91
0.91
0.81
0.86
0.77
0.89
0.85
0.84
0.75
0.84
0.71
0.84
0.91
0.76
0.77
0.95
0.83
0.91
0.88
0.85
0.83
0.78
0.97
0.84
0.75
0.75
0.81
0.76
0.86
0.87
0.86
0.79
0.73
0.95
0.73
0.71
0.83
0.82
0.88
0.93
0.91
0.83
(a) Determine the sample standard deviation weight.
s=0.07 gram
(Round to two decimal places as needed.)
(b) On the basis of the histogram on the right, comment on the appropriateness of using the empirical rule to make any general statements about the weights of the candies.
The histogram is not bell-shaped so the empirical rule cannot be used.
The histogram is bell-shaped so the empirical rule can be used.
(c) Use the Empirical Rule to determine the percentage of candies with weights between 0.7 and 0.98 gram. Hint - x̅ =0.84.
95%
(d) Determine the actual percentage of candies that weigh between 0.7 and 0.98 gram, inclusive.
100%
(e) Use the Empirical Rule to determine the percentage of candies with weights more than 0.91 gram.
16%
(f) Determine the actual percentage of candies that weigh more than 0.91 gram.
__?__%
Homework Answers
a)
Sample standard deviation is given by below formula
Also Using the excel function =STDDEV standard deviation will be
S.D=0.07
b)
Histogram is given as
| Bin | Frequency |
| 0.71 | 2 |
| 0.747143 | 2 |
| 0.784286 | 8 |
| 0.821429 | 6 |
| 0.858571 | 11 |
| 0.895714 | 10 |
| 0.932857 | 6 |
| More | 4 |
The histogram is bell-shaped so the empirical rule can be used
c)
We will Use the 95% Empirical Rule to determine the percentage of candies with weights between 0.7 and 0.98 gram
d)
All of the candies weigh between 0.70 and 0.98. T
Therefore, actual percentage of candies that weigh between 0.70 and 0.98 is 100%.
e)
Here Mean =0.84
Standard deviation=0.07
Let us find the value of Z
Z=(xbar-mu)/sigma=(0.91-0.84)/0.07=0.07/0.07=1
P(Z>1)=0.16
So percentage will be 16%
The percentage of candies that weigh more than 0.91 is given by
This is two standard deviations from the mean. That is 95%.
f)
Actual percentage will be 10%
5 candies weigh more than 0.91. Therefore, actual percentage of candies that weigh more than 0.91 is 5/50 x 100% = 10%.
Add Answer to:
I need help with the final part - (f) Determine the
actual percentage of candies that...
I need help at the bottom with - (d) Determine the actual percentage of candies that...
I need help at the bottom with - (d) Determine the actual percentage of candies that weigh between 0.7 and 0.98 gram, inclusive - Thank you! The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. s= 0.07 gram (Round to two decimal places...
Question Help The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84...
Question Help The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86 0.79 0.73 0.95 0.73 0.71 0.83 0.82 0.88 0.93 0.91 0.83 (a) Determine the sample standard deviation weight. = __?__ gram (Round to two...
Please answer each of the parts in the following question. Show all steps. Thanks in advance!...
Please answer each of the parts in the following question. Show
all steps. Thanks in advance!
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The data to the right represent the weights (in grams) of a random sample of 50...
The data to the right represent the weights (in grams) of a random sample of 50 candies. 0.82 0.83 0.91 0.99 0.71 0.87 0.88 0.76 0.85 0.98 0.87 0.79 0.78 0.77 0.73 0.85 0.89 0.94 0.78 0.75 0.82 0.98 0.81 0.83 0.81 0.89 0.81 0.91 0.78 0.81 0.98 0.72 0.88 0.82 0.89 0.84 0.84 0.89 0.88 0.94 0.81 0.71 0.84 0.85 0.94 0.85 0.82 0.77 0.76 0.84 Complete parts (a) through (f). (a) Determine the sample standard deviation weight. grams)...
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i need help with with c and d. im using the T1-84 calculator
for my class. thank you
X23. The Empirical Rule The following data represent the weights (in grams) of a random sample of 50 M&M plain candies. 0.87 0.88 0.82 0.90 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91 0.86 0.87 0.93 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.91 0.91 0.86 0.89 0.87 0.84 0.88 0.88 0.89 0.79 0.82 0.83 0.90 0.88 0.84...
0.90 0.81 0.88 0.82 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91...
0.90 0.81 0.88 0.82 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91 0.86 0.87 0.93 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.89 0.91 0.91 0.86 0.87 0.84 0.78 0.88 0.88 0.89 0.82 0.83 0.8 0.90 0.88 0.84 0.93 0.90 0.86 0.88 0.92 0.85 0.84 0.84 Another measure of central tendency is the trimmed mean. It is computed by determining the mean of a data set after deleting the smallest and largest observed values. Compute the...
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The data to the right represent the weights (in grams) of a random sample of 50 candies. Complete parts (a) through (f). 0.89 0.85 0.91 0.95 0.75 0.85 0.86 0.75 0.82 0.98 0.86 0.79 0.77 0.75 0.71 0.83 0.82 0.92 0.77 0.73 0.82 0.84 0.82 0.83 0.85 0.87 0.81 0.92 0.77 0.82 0.99 0.73 0.89 0.86 0.87 0.83 0.82 0.85 0.87 0.93 0.82 0.74 0.84 0.89 0.93 0.92 0.84 0.77 0.79 0.83 (a) Determine the sample standard deviation weight gram(s)...
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