I)
Number of electron in Fe = 26
Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d6 4s2
Noble gas having lesser electron than Fe and closest to it is Argon (Ar)
Number of electron in Ar = 18
electronic configuration of Ar is: 1s2 2s2 2p6 3s2 3p6
So, electronic configuration of Fe in noble gas form is: [Ar] 3d6 4s2
It has 6 electrons in d orbital.
2 will be paired and remaining 4 will be unpaired.
So, it is paramagnetic
II)
Number of electron in Zn = 30
Electronic configuration is 1s2 2s2 2p6 3s2 3p6 3d10 4s2
Noble gas having lesser electron than Zn and closest to it is Argon (Ar)
Number of electron in Ar = 18
electronic configuration of Ar is: 1s2 2s2 2p6 3s2 3p6
So, electronic configuration of Zn in noble gas form is: [Ar] 3d10 4s2
It has all the filled orbitals. So, is is diamagnetic
Answer: II
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