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Lecture19: Problem 4 Previous Problem List Next (1 point) 1Q tests are designed so that the mean is 100 points and the standa
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Solution :

Given that,

Population standard deviation = \sigma = 15

Margin of error = E = 3

At 96% confidence level the z is ,

\alpha = 1 - 96% = 1 - 0.96= 0.04

\alpha / 2 = 0.04 / 2 = 0.02

Z\alpha/2 = Z0.02 = 2.054

sample size = n = (Z\alpha/2* \sigma / E) 2

n = (2.054* 15/ 3)2

n = 105.47

n = 106

Sample size = 106

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