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A certain type of elementary particle travels at a speed of 2.50x108 m/s. At this speed, the average lifetime is measured to

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Answer #1

Using time dilation formula,

t'=t\sqrt{}(1-(v​​​​​​2​​​/c​​​​​​2 ))

Given,

t'=2.76x10-6 s

v=2.50x108 m/s

c=3x108 m/s

Therefore putting values,

t' = t√(1-(2.5 x 108/ 3 x 108)2)

=> t' = 0.552t

=> t= t'/0.552 = 2.76x10-6s/0.552

=> t = 5x10-6 s

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