A pair of theoretical enantiomers is named below. For each stereoisomer, draw the structure. Be sure to specify the stereochemistry via wedge-and-dash bonds
This problem is based on the concept of enantiomers.
Isomers that have same molecular formula but different arrangement of atoms in space or different bonding between atoms in such a way that their absolute configuration is exactly opposite are called Enantiomers.
Enantiomers can be determined by using their structure determination and absolute configuration. Enantiomers are non-superimposable mirror image of each other.
The name of first compound is (S)-5,5-dibromo-3-flouro-2-methyl-3-hexanol.
Structure of the compound is given below:
The name of first compound is (R)-5,5-dibromo-3-flouro-2-methyl-3-hexanol.
Structure of the compound is given below:
Ans:Structure of (S)-5,5-dibromo-3-flouro-2-methyl-3-hexanol is as follows:
Structure of (R)-5,5-dibromo-3-flouro-2-methyl-3-hexanol is as follows:
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A pair of theoretical enantiomers is named below. For each stereoisomer, draw the structure. Be sure...
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For the stereoisomers below, use the R/S configuration given in the compound name to finish drawing the structure by connecting the appropriate groups. Be sure to specify the stereochemistry via wedge-and-dash bonds. If needed, you may restore a module to its orignal state by clicking on the module and then clicking on the red over-under arrows.
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