3. (continued) For parts b, c, and d, use the following balanced equation: 2 H3PO4 (aq)...

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3. (continued) For parts b, c, and d, use the following balanced equation: 2 H3PO4 (aq) + 3 Mg(OH)2 (aq) - 6 H20 (1) + Mg3(PO

c. (8 pts.) How many moles of H20 are produced from the neutralization reaction in part b?

Vi d. (10 pts.) The titration of a 15.0 mL sample of H3PO4 requires 13.21 mL of 0.400 M Mg(OH)2 to reach the equivalence poin

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Answer 1

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05.00 2 H3 PO 4 (og) et 3 Mg (OH), (a) — 6420 (1) + Mg 3 (PO4)2 (5) Eve by 07.00 moles of H3PO4 = 3.52 8 = 0.036 moles 98 g 2 2x M / P14) XV Clth Pla) — 3км/часи)) V (Иgton) 5) Bх 15 км. No. 4 x 13:21 - м 3х0.40 к 10. 21 25 - С. 352 м TES:

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3. (continued) For parts b, c, and d, use the following balanced equation: 2 H3PO4 (aq)...