Question

A sample of size

=n47

has sample mean

x

=57.6

and sample standard deviation

=s9.5

.

Part: 0 / 2

0 of 2 Parts Complete

Part 1 of 2

Construct a 99.5% confidence interval for the population mean μ . Round the answers to one decimal place. A 99.5% confidence interval for the population mean is <<μ .

Answer 1

Solution: Given That- Cl 99.5% 57.6 df n-1 df 46 47 n = S = 9.5 99.5% Confidence Level't' is, At a 1 99.5% a 1 0.995 a 0.005 a/2 0.0025 ta/2, df 2.9488 99.5% Confidence Interval for Mean is, At n

CI for Mean using t CI for 99.5% 47 n Mean (X bar) t-value of 99.5% Cl and df 46 std. Dev. (S) SE std.dev./sqrt(n) ME =t*SE Lower Limit Mean ME 57.6 2.9488 9.5 1.38572 4.08618 53.51382 Upper Limit Mean ME 99.5% CI 61.68618 53.5138,61.6862)

At 99.5 %, CI for population mean is,

53.5 < u < 61.7