The reaction below is called the Haber Process and it is the main industrial procedure for...

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The reaction below is called the Haber Process and it is the main industrial procedure for the production of ammonia today.

${\ce {N2 + 3 H2 -> 2 NH3}}\quad \Delta H^{\circ }=-91.8~{\text{kJ/mol}}$

If -1,960.61 kJ of heat was released, how many grams of NH₃ was produced?

Answer 1

Answer #1

91.8 KJ heat released when 2 mole NH3 produced

1960.61 KJ heat released when 2×1960.61/91.8 mole NH3 produced

= 42.714 mole NH3

= 42.714×17 g NH3

= 726.15 g NH3

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Answer 2

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