Question

The reaction below is called the Haber Process and it is the main industrial procedure for the production of ammonia today.

${\displaystyle {\ce {N2 + 3 H2 -> 2 NH3}}\quad \Delta H^{\circ }=-91.8~{\text{kJ/mol}}}$

If 19.290 g of H₂ reacted in excess N₂ how much heat, in kJ, would be released?

Answer 1

Heat is calculated:

q = 19.29 g H2 * (1 mol H2 / 2 g) * (91.8 kJ / 3 mol H2) = 295.14 kJ

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