Question

B) Calculate the boiling point and feeling point of each slution a) 10g of MCI, 100l of us solution b) 10% by mass AL(S ), in water c) 0.10m disodium che (Na CH.D) in water thin each sodium is one ion and the organic citate part is another on

*please write clearly* thanks!

Answer 1

(a) molality of solution = (10g/95.211g/mol)×(1000/100) = 1.0503 molal

i = 3 ( 1 Mg²⁺ and 2 Cl^-)

∆T_b = i.K_b.m = 3 × 0.512×1.0503 = 1.613

∆T_f = i.K_f.m = 3 × 1.86×1.0503 = 5.86

The boiling point of solution is 101.6℃ and freezing point is -5.86℃ . (Answer)

(b)

10% by mass of Al₂(SO₄)₃

Molality =( 10g/342.151g/mol)×(1000/90) = 0.3247molal

i = 5 ( 2 Al³⁺ and 3 SO₄^2-)

∆T_b = 5× 0.512 × 0.3247 = 0.8313

∆T_f = 5×1.86×0.3247 = 3.02

The boiling point of solution is 100.83℃ and freezing point of solution is -3.02℃ . (Answer)

(c)

i = 3 ( 2 Na⁺ and 1 citrate ion)

∆T_b = 3 × 0.512 × 0.10 = 0.1536

∆T_f = 3 × 1.86 × 0.10 = 0.558

The boiling point of solution is 100.154℃ and freezing point of solution is - 0.558℃ . (Answer)