Question

could you explain in details this graph ( Totration of an Amino Acid)

GLYCINE TITRATION CURVE Correio point of pH = 25 (30-16) - 14 mL pila (17.6) = 1l ml p#30 (1-3) - 8 ml PH+3,3 (6-1) = 5 mL Corrected HO Glycine pH 9.3 (17-1)-6mL. PH 10.1 (23-4) 19 mL pH=10.3 (26-6)= 20mL pH=10.5 (29-8) = 21 mL 30mL 25mL 20m 15ml 10mL 5m Om 5ml 10ml 15mL 20mL 5ml 30ml Titrale with HCA Titrate with NaOH.

Answer 1

litrason involves graduak addition of Ht voorlon to a solution. In Acidic environment, glycine has a net positive charge lets say pH of soil is 1 vehich means there are so many Htion's in the solution. As me add Nowh, the onions are neuhelised by ttion and so the pH of son starts increasing. At pt= At $1= 2.34, the glycine's cashoxyl grizek donates its H ion _ As a result of this the Neoni gek neutraliseden As the caulimeyl gurub of so many dyine molecule au donating Htions, pl remains constant Once the carboxyl group of All the glyene molecules have clonated theis Ht, The Twitter addition of onion causes ta sudden rise in pH Al At this stage the glycine become's zwitter son. Nowe futher addition of of ions cause rise in pH about 7 at pH=9.6, the ammonium group of glyene starts donating its Htion and hence the pH remains constant at 9:6 And futher addition of Ht ion causes further rise in pH of *PI -5.9 pk, 22.34 Please Like If this was Helpful for you!