Question

!? Verify Kirchhoff’s Current law (I) in = (I) out for junction point “X” in the circuit

point 560 Ω resistor 1000 Ω resistor 4.5 . 1 |ー オー1 ered battery box1 -T 10000 Ω resistor 17 black 1 Is switch (closed for measurements only) +1 To measure each current, the wire it is flowing through must be "cut" (disconnected) and the ammeter inserted in series. COM Do not place the ammeter across a component, as this may damage the meter Measuring Is with the ammeter. Figure 2. Circuit for the study of Kirchhoff's Current Law. Prediction: To which other current(s) (I.. 1s, 1s 1 and 1i) do you expect 1, 13, Is to be equal? I also 's, also e's, Is also 4S Now measure each of the labelled currents. One at a time, disconnect each wire (either end or both) and connect the ammeter in series, close the switch and record an I, value. Note the current can flow through the meter in two directions and Figure 2.(b) shows the convention. If the meter displays a positive value (no sign preceding the number), then the current is flowing out the COM terminal. Open the switch, take the ammeter out and return the circuit to the original configuration 2(a) and do the next current. Verify Kirchhoffs Current Law ( Σ(Don-Σ(l)out) for junction point X in the circuit.

Answer 1

if we apply KCL at junction X that is sum of current coming in is equal to sum of current going out then we can write

I1 = I2 +I3

i.e LHS = I1 = 3.29 mA

RHS = I2 + I3 = 2.82 mA + 0.473 mA = 3.29 mA

hence KCL is verified

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