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Please what the answer for these two questions!?
rent Introductory Physics Lab Kirchhoffs Circuit Lawas and Equivalent The multimeter manual specifies measurementermanual specifies that the relative uncertainty is 0.5% for any Recall that if Calculate the absolute uncertainty () and (o)2 for each component in table 1 then, by the o uncertainty propagation addition rule. (last column in the table) Table 1, Measured voltages from the circuit for the study of Kirchhoffs Voltage Law uncertainty calculations battery box 30 . То,0735 560 Ω res stor l--, 213-o.co. 215-525 1000 Q resistor2 10000 Ω resistor 4.02 closed switch o.o0 Add the voltages and record this in sum of above (2aV)). What assumption is made concerning the voltage drops across any of the wires and connections? Is Kirchhoffs Voltage Law ( Σ(AV), Explain your reasoning. 0 ) verified within experimental uncertainty in the sum? Testing Kirchhoffs Current Law A junction, or node, is a point in a circuit where two or more wires are connected together. Kirchhoffs Current Law, which is also called Kirchhoffs Junction Law,states that the total electrical current entering the junction equals the total electrical current leaving the junction: (textbook, Sec. 28.2) This law states that current is conserved in every junction. Since current is a flow of charges, this in effect means that no electrical charges are created or destroyed. Construct the circuit in Figure 2(a).
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Answer #1

in the first question here we are assuming there is no loss of energy in the experiment process like loss due to heat in wires ,

the resistance of resistors is also not varying with time, connections are tight (no sparking), connections are also considered with zero loss of energy means there is no resistance occurring on connection site (suppose the connection is like wires are only touching not connected together then there will be resistance in flow of electrons which will create extra resistance which is we are assuming is not the case here), wires are highly conductive (no heat loss).

Here, in this case, Kirchhoff's voltage law isn't verified within experimental uncertainty because deltaVsum is always greater than the minimum deltaV(V) which means the error which we are getting is greater than the error which can occur due to multimeter measurements (technical error) that means the setup is somewhere wrong that's why we are not getting (ΔΙ .) i =0

up to the the errors.

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