Question

[1] Water flowing in a pipe is determined to be moving at the velocities given in the diagram below. The higher level is 3 meters above the lower one and the pressure in the lower portion is measured to be 200 kPa. Determine the pressure inside the upper pipe Treat the water as an ideal fluid obeying Bernoulli's equation. Consider the path connecting poin in the lower pipe with point 2 in the upper pipe a streamline 200 kPa 2.0 m/s ater Bernoulli's equation is Using p-200 kPa-2.00 × 105 Pa. p 1000 kg/m*, y-y,-3.0m, v,-2.0m/s, and v,-3.0m/s, P2- 2.00 x 105 Pa (10 kg/m)[(2m/s)2 - (3m/s)] +(10 kg/m(9.81m/s')(-3m) - 1.68 x 105 Pa If the upper pipe has an open end, we can also determine the velocity of the water just outside the opening Pin = 168 kPa, v.-3.0 m/s Pour = Parm-10 1 kPa 168kPa + ½ ( 10, kg/m')(3m/s)-101 kPa ÷ ½ (10' kg/m) w (168kPa-101 kPa)/1% (10' kg/m")] + 9 (m/s)'-vout2-143 (m/s)' Vout [143] m/s = 12 m/s
Ignore question [1], just need the problem description from it.

Answer 1

piseuille sと LA 2.