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A 2L bottle is filled with water and has a 2mm diameter hole in the side 2cm from the bottom and the top is open to the atmosphere. a) What is the velocity of the water stream coming out of the hole when the water is 10cm above the hole? Treat the water as an ideal fluid obeying Bernoullis equation. Additionally, you may assume that the flow is slow enough that the velocity of the water at the top surface is negligible. Hint: choose a point on the top surface and a point just outside the hole as the two points for the Bernoullis Law calculation b) Does your answer change as the atmospheric pressure changes?[1] Water flowing in a pipe is determined to be moving at the velocities given in the diagram below. The higher level is 3 meters above the lower one and the pressure in the lower portion is measured to be 200 kPa. Determine the pressure inside the upper pipe Treat the water as an ideal fluid obeying Bernoullis equation. Consider the path connecting poin in the lower pipe with point 2 in the upper pipe a streamline 200 kPa 2.0 m/s ater Bernoullis equation is Using p-200 kPa-2.00 × 105 Pa. p 1000 kg/m*, y-y,-3.0m, v,-2.0m/s, and v,-3.0m/s, P2- 2.00 x 105 Pa (10 kg/m)[(2m/s)2 - (3m/s)] +(10 kg/m(9.81m/s)(-3m) - 1.68 x 105 Pa If the upper pipe has an open end, we can also determine the velocity of the water just outside the opening Pin = 168 kPa, v.-3.0 m/s Pour = Parm-10 1 kPa 168kPa + ½ ( 10, kg/m)(3m/s)-101 kPa ÷ ½ (10 kg/m) w (168kPa-101 kPa)/1% (10 kg/m)] + 9 (m/s)-vout2-143 (m/s) Vout [143] m/s = 12 m/s

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