Question

t Resolving Vector Components with Trigonometry Find to con s one vecter Awn wyn .soo and angeo-200.ฟ" eesped totrn xunwa mon n Fgun1). Enter numenicalty separated by a comma, thex component tollowed by the y component Constans View Available 9mms eiem abroe ๙ magntude T 2Nnadeedion@-35, nom of east ma a poed oas to thers of vechors, hower to calculate resuits with veclars, a is best to seled a coordnane systen and manpdate the n that coordinate syste VO AZ Part B Enter num encaly, separated by a c-, component Sollu-by the y component Figure 1of1 ▼ Part C Fndthe components otthe vedorCwmwnghes 100 and ange φ-300° as shown m Enter numenically, separated by aconma, the x component Sllowed by the y component View Available Hinls

Answer 1

Part A a = 1.00 m, alpha = 20.0 degrees x-component, A_x = a cos alpha = 1 times cos 20 degrees = 0.94 y-component A_y = a sin alpha = 1 times sin 20 degrees = 0.34 therefore A^vector = 0.94, 0.34 Part - B b = 1.00 m, beta = 20.0 degrees x-component, B_x = b cos beta = 1 times cos 20 degrees = 0.94 y-component B_y = b sin beta = 1 times sin 20 degrees = 0.34 therefore B^vector = 0.94, 0.34 Part-c c = 1.00 m, phi = 30.0 degrees x-component C_x = c sin phi = 1 times sin 30 degrees = 0.50 y - component c_y = c cos phi = 1 times cos 30 degrees = 0.87 therefore c^vector = 0.50, 0.87