Il See Periodic Table See Hin If all of the energy from burning 254.0 g of...

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Answer 1

Answer #1

ΔH=-2220kJ/mol

molar mass of propane=44.1g/mol

given mass =254g

number of moles of propane present=254g/44.1g/mol=5.75mol

total heat from propane =5.75mol*2220kJ/mol=12765kJ

Q = mc∆T

Q = heat energy (Joules, J)=12765kJ

m = mass of water=?

c = specific heat =4.18 kJ/kg⁰C

∆T = change in temperature of water=100-20=80⁰C

so 12765kJ=m*4.18 kJ/kg⁰C*80⁰C

So m=12765kJ/4.18 kJ/kg⁰C*80⁰C =38.17kg

mass of water needed =38.17kg

volume of water needed =38.17kg/1 =38.17L

thank you

Answer 2

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