Question

Nuclear reactions can be used to produced short lived isotopes that are of interest to study nuclear properties. For example, the nuclear physics group at UT will measure the decay of 29F (Z=9) in MSU next year. Fluorine-29 will be produced in the fragmentation of a 48Ca beam, resulting in 29F, 2 neutrons and a fragmentation partner. (a) What is the fragmentation partner of 29F? (b) What is the Q value of the fragmentation reaction? Do we have to provide that energy or we get it for free? (c) Fluorine-29 is very interesting because it's at the neutron dripline, the point at which nuclei are not bound anymore. Assuming 29F mass is 29.043103 u, what is its binding energy? Is it bound?

Answer 1

Ans A Here the 2 Car splits to produce gft and a fragmentation partner and let it be X , then the nuclear reaction is given as 48 la F +2 ont X .. from conservation of charge, we have 2029tZ = z=11 Hence, from mass conservation we have. 48=29 +2t A - A=17 e the element is having Z=11 and A=17, which is Sodium. 170 The Q-value is the disintegration energy and we get it for free when the sola nucleus disintegrates. Q = Ame' =Moçante)MCF 9) -8 m,- M(N) Mere, ma = mass of neutron ; ML, (a) = mass of MLF) = ass of Ikrovine isotope M/N027) 0 = mass of sodium isotope. Calium nucleus

@ The binding Energy is for A 2 29, 2=9 mass defect Ena Ame 2 ; c= 3x 103 m/s = speed of light E b = [(A-2)mn + Zme - ml n vacuum. T E6 = 120x160086654ut 961.007 28 4-2 9. 0431034) 6² E6= 0.1956 197 amu.c? But lomu = 93105 Mev 2 i Eb=0. 195617x931.5 TE 6= 182.217 Mev / Ans. Hence the nucleus is bound D29