Proton separation energy is the energy required to remove one proton from the nucleus.
Thus
, where Sp = Proton separation energy
Neutron separation energy is the energy required to remove 1 neutron from the nucleus
, where Sn = Neutron separation energy
The original mass 12C nucleus = 12.00000 amu
= 0.098931u
Energy released per amu = 931.5 MeV
Total BE = 92.15 MeV
12C ,if bereft of 1 proton becomes 11B
BE of 11B = 92.15MeV ( as per tables)
Sp = BE of 11B-BE of 12C = 76.20 Mev - 92.15 MeV = -15.95 MeV
BE of 11C = 6x 1.00864u + 5 x 1.007276u + 6 x 0.000054858u - 11.000 u = 0.088554 u = 82.44 MeV
12C bereft of 1 neutron becomes 11C = 92.15 MeV - 82.44 MeV = 9.71 MeV
Note: I am allowed to solve only one problem and upto 4 parts of the same problem. In this case part(c) onwards is diffrent problems.Hence can not be solved.
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