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The Mole (1.5 pt) If you plan to dissolve 0.075 moles of sucrose (C12H2011) to make 150 mL of solution (a) How many grams of sucrose should you plan to measure out? (b) What is the molarity of the resulting solution?
If you plan to dissolve 0.075 moles of sucrose (C12H22011) to make 150 mL of solution... (a) How many grams of sucrose should you plan to measure out? (b) What is the molarity of the resulting solution?
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Shape, melting point & solubility (2.5 pts) When melting or boiling a substance (both of which are physical changes), which kinds of attractions may be broken? Circle all that apply. hydrogen bonding covalent bonds dipole-dipole London forces If I told you that only one of these molecules is a solid at room temperature, which one is that more likely to be? How can you tell from...
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Identifying Chemical Reactions (2 pts) Pro ho fan cost can Name the organic reaction happening at each of the following steps in the Krebs cycle (pictured at right): (a) succinate → fumarate waloncette Malate (b) fumarate → malate Fumarate Pumarte o a-ketoglutarala Succinyl-CoA Succinate (c) malate → oxaloacetate (d) isocitrate → a-ketoglutarate* (two rxns!!)
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Intermolecular Forces and Boiling Point (3 pts) Formaldehyde (CH2O) appeared in your exam. (a) Use Lewis structures to show a molecule of formaldehyde forming hydrogen bonding attractions with a molecule of water. CLEARLY identify the donor and acceptor in this drawing. (b) Referring to your drawing above, briefly explain why two formaldehyde molecules can't form hydrogen bonding attractions between each other. (c) Formaldehyde molecules are twice...
When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when thinking about stoichiometry. However, when we dissolve a solid (also known as a solute) in a solvent to form a solution, the solute becomes evenly distributed throughout the solution and we need to know how many moles of solute are present in a particular volume of solution. pt. 1 A solution is created by dissolving 10.0 grams of ammonium chloride in...
Please clear answer and if you can avoid hand writing. Thanks ahead. An unknown triprotic acid (so “n” = 3) sample of mass 0.225 g required 38.22 mL of 0.09767 M NaOH to neutralize where 2.14 mL of 0.1015 M HCl was used to back titrate, find the molar mass of the unknown solid acid in grams per mole.
When chemists work with solid materials, we simply weigh out amounts of solid reagents and calculate mole amounts when thinking about stoichiometry. However, when we dissolve a solid (also known as a solute) in a solvent to form a solution, the solute becomes evenly distributed throughout the solution and we need to know how many moles of solute are present in a particular volume of solution. Pt1:A solution is created by dissolving 13.0 grams of ammonium chloride in enough water...
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A spring stress 0.150 m when a 0.300 kg mass is gently suspended from it as fig below. The spring is then set up horizontally with 0.300 kg mass resting on a frictionless table. The mass is pulled so that the spring is stretched 0.100 m from the equilibrium point, and released from rest. Determine: a) the spring stiffness constant K; b) the amplitude...
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moles of 1. You are given 41 0.0 mL of a 1.581 M KC03 solution. There are K present in the solution. (Fomula) CONCENTRATION MOLES VOLUME 2. You are given 83.5 mL of a 2.101 M solution of AgNOs. If all of the water is allowed to evaporate, then the mass of AgNO3 left in the container is g. 3. If 25.0 ml of a...