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6. A uniform rod of length 5.0 m and weight 60.0 N is supported at its right end by a vertical cable and at a point 1.5 m fro
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Answer #1

here,

the length of rod , l = 5 m

weight , W = 60 N

taking moment of force about the point where T1 is connected

T2 * 3.5 - W * (l/2 - 1.5) = 0

T2 * 3.5 - 60 * (5/2 - 1.5) = 0

solving for T2

T2 = 17.1 N

the tension in cable 2 is 17.1 N

equating the forces vertically

the tension in the cable 1 , T1 = W - T2

T1 = 60 - 17.1 N = 42.9 N

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