here,
the length of rod , l = 5 m
weight , W = 60 N
taking moment of force about the point where T1 is connected
T2 * 3.5 - W * (l/2 - 1.5) = 0
T2 * 3.5 - 60 * (5/2 - 1.5) = 0
solving for T2
T2 = 17.1 N
the tension in cable 2 is 17.1 N
equating the forces vertically
the tension in the cable 1 , T1 = W - T2
T1 = 60 - 17.1 N = 42.9 N
6. A uniform rod of length 5.0 m and weight 60.0 N is supported at its...
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