Question

1. A uniform 40.0-kg scaffold of length 6.0 m is supported by two light cables, as shown below. An 80.0-kg painter stands 1.0 m from the right end of the scaffold, and his 2.5 kg painting equipment is 1.5 m from the left end. a) Draw an FBD of the scaffold and clearly label all the forces acting on the scaffold b) Summing the torques acting on the scaffold, find the tension in the right-hand cable. Summing the forces acting on the scaffold, find the tension in the left-hand cable c)

Answer 1

An - Curen mi= 40kg, M ookg, mpe = 2.5kg gran free body eleagram - A losm I losmt om at " may mg Here T. Tension in left side TRS " " Reght . mpe mau of painting equipment my - man of scaffold. mms man of sian Take for que about point AT & TATO or (Mig) (1.5m) + (mig) (3m) + (mma x15m) - TR 6m). ③ or (2.5 13 19.811%) 105m) + (40 g) (9.814) (3) + ( 80kg) (9.818/2) 5 m) - 6 Te Te = 856.33N 6 © EFY20 TL + TR - mpeg-meg-mingo of Te+ Tp- (Moeft ms + Mn ) 2 20 or TL = (2.5kg + 40 leg + dokg) (1 . 0144, 2) – 876.33N T-3 45.40N)