Question

The flywheel of a steam engine runs with a constant angular velocity of 230 rev/min. When steam is shut off, the friction of the bearings and of the air stops the wheel in 2.5 h. (a) What is the constant angular acceleration, in revolutions per minute-squared, of the wheel during the slowdown? (b) How many revolutions does the wheel make before stopping? (c) At the instant the flywheel is turning at 115 rev/min, what is the tangential component of the linear acceleration of a flywheel particle that is 43 cm from the axis of rotation? (d) What is the magnitude of the net linear acceleration of the particle in (c)? (a) Number (b) Number (c) Number (d) Number Units Units Units Units

Answer 1

iver wo = 230 reu/min o 5 x 2TT usheel teps afte -5hy 4 uing urten ot anquly motion Radia anqulau greleiation O230a5 X 60 a-O.15333 eu/min2 2 -(R.ov2)x43X1o a 0-1933 Yel/mi 62-362 mls (b uing equion thv the tlyurheel make a Jaita befee uteppi ng (no q ceuolution) (6R.362)C.cco u5) e- wot 2 62-362 m/s - 230(5 x60)-x(o-15 33)(5 x 60 0 34500 1724:625 e 32775 Teu 1# Tangatal (emponent ot uneas arreluntien et fyoheel thnt iu 43cm at Y - o-1533 x ax 43x16 во? -O.o0o115 m/s Aulos velocuhy ot pautcle in ras