The angular speed of an automobile engine is increased at a constant rate from 1470 rev/min...
The angular speed of an automobile engine is increased at a constant rate from 1470 rev/min to 3320 rev/min in 8.16 s. (a) What is its angular acceleration in revolutions per minute-squared? (b) How many revolutions does the engine make during this 8.16 s interval?
Homework Answers
(a)the angular acceleration is calculated as follows:
ωf = ωi + αt
α = (ωf -ωi)/t
= (3320 - 1470)/(8.16/60) =
13602.94 rev/min2 = 13.6x10^3
rev/min^2
(b)
Number of revolutions made by the engine in8.16 s is,
θ =(1/2)( ωi+ωf)t =(1/2)(1470+3320)(8.16/60) = 325.72 rev
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