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A flywheel with a diameter of 1.60 m is rotating at an angular speed of 320...

A flywheel with a diameter of 1.60 m is rotating at an angular speed of 320 rev/min.

(a) What is the angular speed of the flywheel in rad/s?
rad/s
(b) What is the linear speed of a point on the rim of the flywheel?
m/s
(c) What constant angular acceleration (in revolutions per minute-squared) will increase the wheel's angular speed to 1000 rev/min in 60 s?
rev/min2
(d) How many revolutions does the wheel make during this 60 s acceleration?
rev

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Answer #1

Given data The diameter is d = 1.6 m a) The angular speed of the flywheel is, 6-320 rev/min 27T 60 33.51 rad/s 320 b) Ihe linear speed 1s, 16 (83.51) 2 26.81 m/s c) The angular acceleration is 1000 rev/min-320 rev/min 60 s 1000 rev/min- 320 rev/min 1 min = 680 rev/min d) The number of revoluti ons is, 2 (1000)+(320)) (60 s) (1000)+(320)) (1 min) - 660 rev

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