1) slope of object 1 = 1.2754 ( from graph)
slope of object 2 = .7249 ( from graph )
2) Linear graph represents that there is no acceleration in object.
3) Object 1 moves faster because slope is higher that is velocity.
Part - 2
1) x vs t^2 graph is linear
2) it means there is uniform acceleration in object 3.
3) acceleration of object 3 was 31.774 unit. 2*slope = acceleration
Answer analysis part 1 and part 2 show work & clear enough to read! PHY 1100-...
PHY 1100- Exercise 2- Report Name: Part 1 -Velocity Position versus Time (x vs t0 graph for Object 1 x versus t- Object 1 y 1.2754x+0.0187 Linear (x) t(s) Position versus Time (x vs t) graph for Object 2 x versus t- Object 2 4.5 3.5 -0.7249x+0.0513 2.5 Linear () 1.5 0.5 t (s) Position versus Time (x vs t) graph for Both Objects x versus t for Both Objects y 0.7652x+0.0187 Linear (x) -0.4349x+0.0513 0.6 12 1.8 2.4 3...
HELP NEEDED!!!!!!! especially with the graphing for objects 1
and 2 together and object 3 squared. People are getting different
graphs and I do not know if it is correct. Also SIG FIGS in
analysis. THANK YOU IN ADVANCE
Part 1 - Velocity Position versus Time (x vs t) graph for Object 1 x versust-Object 1 y 1.2754x+ 0.0187 x (m) Linear (x (m)) 0 Position versus Time (x vs t) graph for Object 2 x versus t-Object 2 4.5...
What does the fact that this particular graph is linear indicate
about the acceleration? What is the acceleration of Object 3?
Exercise 2 Report - Word References Mailings Review View Easy Document Creator A.y.A- 를 15-12-B- 11 Heading 111Normal! Subtitle Paragraph Position versus Time 2 (x vs tA2) for Object 3 45 40 35 30 25 20 15 10 40.3 : 34.9 y 0.0628x + 03256 25.5 20.1 15.2 118 8.4 4.3 5 061 100 200300 400 500 600 tA2...
7:32 0 . 18% 5 Col20628 il y Pow To (a) The graph below plots the position versus time for an object moving in one dimension along the x direction. What is the speed (magnitude of velocity) of the object at. The graph plots position vs. time, not velocity vs. time. To find velocity, think about the definition of instantaneous velocity and how it is related to position. Notice the graph is a straight line from .. . Can you...
could u explain why 10b is AB and could you explain to me why
we cant tell why acceleration has direction
10. Use the acceleration vs. time graph on the right to indicate where the line would be on the graph (somewhere in box A. somewhere in box B. either box AB, or at m/s) in the following situations. An object at rest. Acceleration vs. Time A positive velocity. A An object slowing down in the positive direction. I Time...
An object travels with a constant acceleration for 10 s. The vectors in the figure represent the final and initial velocities. Move the endpoints of the lines in the plots to graph the x-component of the velocity versus time, the y-component of the velocity versus time, and the y-component of the acceleration versus time. 20 m/s 30° Velocity vs. time 20 16 12 30V 6 2 20 m/s 2 -6 -8 -10 -12 -14 about usca privacy policy terms of...
1 of 5 MEDGAR EVERS COLLEGE Basic Physics PHY 114 -w-01 Department of Physical and Compater Sciences Medgar Evers College Workshop Lab 2: Motion in One Dimension Name: Name: Name: Sketch the requested graphs Sketch the position versus time graph whose function is r(t)- -6 t-51 if9ss 12 Position versus Time r(m) t(s) 12 3456789 101112 -6 -8 Sketch the velocity versus time graph derived from the position versus time graplh Velocity versus Time r(m/s) 12 34567890 12 -2 -4...
2986/3100 Resources ch An object travels with a constant acceleration for 10 s. The vectors in the figure represent the final and initial velocities. Move the endpoints of the lines in the plots to graph the x-component of the velocity versus time. the y-component of the velocity versus time, and the y-component of the acceleration versus time 20 mis Velocity vs. time 20 m's Acceleration vs. time 5 6 8 9 100 Resourc -2 -6 -8 10 12 14 16...
An object travels with a constant acceleration for 10 s. The vectors in the figure represent the final and initial velocities Move the endpoints of the lines in the plots to graph the x- component of the velocity versus time, the y-component of the velocity versus time, and the y-component of the acceleration versus time. 20 m/s 30° Velocity vs. time 18 16 30° 7 12 10 4 20 m/s 2 -4 -6 -8 -10 -12 -14 Velocity vs. time...
constant velocity and constant acceleration experiment pls
only correct answers and clear handwriting thanks
General Form of Linear equation Y=mx+b m is the slope b is the y-intercept General Form of Quadratic equation y=A+BX+C A is the quadratic coefficient B is the linear coefficient C is the Constant Constant Velocity (Motorized Cart) 10 Pistol 05 Times Y=mx+b X=Vt+Xo m is the slope: m is the Velocity = 0.210 m/s (21 cm/s) b is the y-intercept: b is the initial Position...