constant velocity and constant acceleration experiment pls only correct answers and clear handwriting thanks General Form...
Constant Positive Accederation Recall that acceleration is the slope of the v-t graph Position vs. Time Time (s1 Position ml Velocity bos) 0 0.2 2.5 0.4 1.5 0.5 0.6 Velocity vs. Time 0.8 1.2 2.5 1.4 0.5 Timet s 1 1.6 Acceleration vs. Time 1.8 0.5 1.5 s utat V ut at Timet S i 5 15
2. (a) Explain the difference between constant velocity and constant acceleration. (b) Are you more likely to be able to walk at a constant velocity or at constant acceleration? (c) For the equation x = Xo + of + at, what does a graph of x versus t look like? (d) What does the graph look like if a -0? Please scetch graphs and give explanations. (7 pts) 2 3. For the following position versus time values, calculate the average...
2. Calculate the velocity at each time (except the first and the last one) by using values immediately after and before those times: the tn-- For example, the velocity at point 2 is n Time t (s) Position x (m) Velocity v (m/s) vt (unit-mls) aGou .245 8 3,abus 1.553 3. calculate v/t (what are the units?) and write it in column 5 of the table above. Calculate its average and its uncertainty: Average uncertainty: 4. On the graph paper,...
Please note that X is time Value Position vs Time Linear Fit m y = mx + b Quadratic Fit Α. B 0.305 -0.0583 y=0.305x -0.0583 4 1 0.110 -0.0663 0.195... yöllx'-0.0663x7.195 |(1.550, 0.359) 1(1.600,0.373) 0.28 y = Ax?+ Bx + C (x1, yı) (x2, Y2) Slope For Position vs Time data: (a) Did your quadratic fit of this graph provide initial position? If yes, what is its value? (4 points) (b) Did your quadratic fit of this graph provide...
1. To confirm the linear relationship between acceleration and force, established by Newton's Second law, a student collected data. Using the collected data he made a plot of system's acceleration vs applied force. The mass of the moving system remained constant during the experiment. This graph will be used for the following questions: 1; 2; 3; 4. Determine the experimental mass of the system using the information provided in the graph: acceleration vs applied force. Submit answer in kilograms. Use...
5. During a lab, you measure the below data of velocity vs. time for a cart undergoing constant acceleration in an experiment. What is the acceleration of your cart? Velocity vs. Time 200 180 160 140 y(t)-b+mt Fit Result: 120 100 b-0.5 80 m-2 60 40 20 180 12 40 60 80 100 Time [s] 10 Velocity [m/s] 20
constant force mass (g) acceleration (m/s2) 300 10F/3 550 100F/55 800 10F/8 1050 100F/105 Include graphs of mass on the x-axis vs acceleration on the y-axis and inverse mass on the x-axis vs. acceleration on the y-axis. Slope of the line for the second graph only: _________ (include units) Questions: According to Newton’s Second Law, F = ma, the equation has a y-intercept of zero. How does the graph of force versus acceleration for a system of constant mass support...
can someone help me out on question 3 also part a,b and c your result in the form y = mx where V corresponds to y and f Fanation 2 for V. Express your result in Sohe Equad y = energy in ev ors corresponds to : V=hv y=mx X=vl m = 9 h v on't use data) a graph of V as a function of f. Use the back of this page for a Sketch (i.e., don't use de...
need help with ANALYZE PART A AND B and FINALIZE EXPLORE A car is moving with constant acceleration along a straight road (A) Determine how the velocity and the displacement of the car vary with time if the car is initialy moving to the right with a speed of 9.0 m/s and has an acceleration to the right of 1.7 m/s (B) Determine the velocity as a function of time when the velocity is instead initially to the right and...
Velocity v (m/s) v/t (unit= 2 Time t(s) 10.1004 10.3006 0.5008 0.7011 0.9014 1.1017 11.3021 1.5026 Position x (m) 0.149 0.195. 6.271 0.366 0.474 0.599 0.735 0.881 5 0.305 10.427 0.507 10.592 10.651 0 103 1.013624 0.95268 0.722778 0.64 5249 0.591232 0.540218 8 3. calculate w/t (what are the units) and write it in column 5 of the table above Calculate its average and its uncertainty (with units): Average: >0.728 m 1x uncertainty: N e ma max- () mun =...