ZuoTi.Pro
Question

constant force mass (g) acceleration (m/s2) 300 10F/3 550 100F/55 800 10F/8 1050 100F/105 Include graphs...

constant force

mass (g)

acceleration (m/s2)

300

10F/3

550

100F/55

800

10F/8

1050

100F/105

Include graphs of mass on the x-axis vs acceleration on the y-axis and inverse mass on the x-axis vs. acceleration on the y-axis.

Slope of the line for the second graph only: _________   (include units)

Questions:

  1. According to Newton’s Second Law, F = ma, the equation has a y-intercept of zero. How does the graph of force versus acceleration for a system of constant mass support this relationship?

  1. Compare the slope of the line to the total accelerating mass. Comment on the two values, and the expected relationship between them if the second law is true.

  1. Newton’s Second Law, F = ma can be re-written as: a = F(1/m). How does the graph of acceleration versus inverse mass for a system of constant force support this relationship?

  1. Compare the slope of the line to the constant applied force. Comment on the two values, and the expected relationship between them if the second law is true.
science   Advanced-Physics   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

0 0
Add a comment
Know the answer?
Add Answer to:
constant force mass (g) acceleration (m/s2) 300 10F/3 550 100F/55 800 10F/8 1050 100F/105 Include graphs...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • looking for the rest of the answers to pages 5-2, 5-6. (graphs are included at the...

    looking for the rest of the answers to pages 5-2, 5-6. (graphs are included at the end) DATA 722.1 Mass of cart with plastic box mounted on it- Mass constant, resultant force varied 0:78 Total moving mass =_7799-m: Acceleration (in m/s Resultant Force 0.1728 0.196 20 gm wt = nt G-311 gm wt = 0.39Z 40gm wt = 0-$584 Resultant force constant, mass varied Resultant forceo gm wt-9.49 nt Reciprocal of total moving mass (Can be obtained when use Excel...

  • 1. To confirm the linear relationship between acceleration and force, established by Newton's Second law, a...

    1. To confirm the linear relationship between acceleration and force, established by Newton's Second law, a student collected data. Using the collected data he made a plot of system's acceleration vs applied force. The mass of the moving system remained constant during the experiment. This graph will be used for the following questions: 1; 2; 3; 4. Determine the experimental mass of the system using the information provided in the graph: acceleration vs applied force. Submit answer in kilograms. Use...

  • Question 7 is related to the force vs mass graph that is provided and the first...

    Question 7 is related to the force vs mass graph that is provided and the first section of the excel sheet. Question 3 has to do with the force bs acceleration graph and second section of the excel sheet. The first two files are showing the equations that are supposed to be used to find these answers. Any help would be greatly appreciated. I mainly need assistance on number 1 and 2 now. The question with the free body diagram...

  • Data Trial 1 Trial 2 Trial 3 Distance travelled by mass, S (m) [Same for each trial) 05 m 0.5 m 0...

    Data Trial 1 Trial 2 Trial 3 Distance travelled by mass, S (m) [Same for each trial) 05 m 0.5 m 0.5 m Total mass moved (M+m) (KG) 03284 .?'to. same in all trials Hanging mass (m) [different in each trial] Time between gates, t (sec) 14 It% |t2-O-68 t3 #0.99 d Experimental Acceleration, dexp (m/s) (use: S vot t ^at2) 4 165 mls try to make vo Theoretical Acceleration, athe (m/s2) (use: aINM+m Difference (%) mg 15.3 Task 1:...

  • Vibrational Motion Introduction If an object is following Hooke’s Law, then Fnet = -kx = ma...

    Vibrational Motion Introduction If an object is following Hooke’s Law, then Fnet = -kx = ma Since acceleration is the second derivative of position with respect to time, the relationship can be written as the differential equation: kx = m δ2xδt2/{"version":"1.1","math":"<math xmlns="http://www.w3.org/1998/Math/MathML"><mi>k</mi><mi>x</mi><mo>&#160;</mo><mo>=</mo><mo>&#160;</mo><mi>m</mi><mo>&#160;</mo><mfrac bevelled="true"><mrow><msup><mi>&#948;</mi><mn>2</mn></msup><mi>x</mi></mrow><mrow><mi>&#948;</mi><msup><mi>t</mi><mn>2</mn></msup></mrow></mfrac></math>"} Methods for solving differential equations are beyond the scope of this course; in fact, a class in differential equations is usually a requirement for a degree in engineering or physics. However, the solution to this particular differential...

  • Question 3: In order to determine the force of friction and the coefficient of kinetic friction,...

    Question 3: In order to determine the force of friction and the coefficient of kinetic friction, you will use Vernier Video Analysis to find the acceleration of the cart. You will use the following video to determine these values. Download the following video and open up Vernier Video Analysis, and then import the video into the program. You need to begin your analysis after the hand is no longer pushing the cart and finish when the cart has come to...

  • the question is in last picture. i provided the lab content... I need guidance. thank you....

    the question is in last picture. i provided the lab content... I need guidance. thank you. INVESTIGATION 10 ROTATIONAL MOTION OBJECTIVE To determine the moment of inertia I of a heavy composite disk by plotting measured values of torque versus angular acceleration. THEORY Newton's second law states that for translational motion (motion in a straight line) an unbalanced force on an object results in an acceleration which is proportional to the mass of the object. This means that the heavier...

  • 2 Experiment: In the experiment conducted, the mass of the counter weight M was chosen to...

    2 Experiment: In the experiment conducted, the mass of the counter weight M was chosen to be 50.0 +/- 0.1 g The mass of the rubber stopper was measured to be 12.0 +/- 0.1 g The stopper was spun at five different values of the radius (measured with a meter stick). For each value of r, the time to complete 10 full revolutions was measured with stopwatch. The following data was collected: 40.0 60.0 80.0 100.0 (cm) 1) 120.0 10.74...

  • Learning Objectives As part of this activity, you want to be able to: Experimentally verify that...

    Learning Objectives As part of this activity, you want to be able to: Experimentally verify that the strength of the Coulomb force between two charged bodies varies inversely with the square of the separation distance between them. Experimentally verify that the strength of the Coulomb force between two charged bodies varies with the product of the charges. 1.1 Pre-lab Gravitational force Last semester you may have encountered Newton's universal law of gravitation. This law, which describes the force between two...

  • please answer all prelab questions, 1-4. This is the prelab manual, just in case you need...

    please answer all prelab questions, 1-4. This is the prelab manual, just in case you need background information to answer the questions. The prelab questions are in the 3rd photo. this where we put in the answers, just to give you an idea. Lab Manual Lab 9: Simple Harmonic Oscillation Before the lab, read the theory in Sections 1-3 and answer questions on Pre-lab Submit your Pre-lab at the beginning of the lab. During the lab, read Section 4 and...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT