Homework Answers
P(defective transmission)=P(factory A and defective transmission)+P(factory A and defective transmission)+P(factory A and defective transmission) =0.32*(1/178)+0.41*(1/220)+0.27*(1/204)
=0.004985
therefore P(factory B given defective)=0.41*(1/220)/0.004985 =0.373855 ~ 0.3739
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