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We will be analyzing the built-in R dataset: ‘AirPassengers. Carefully read through all the R code and associated output bel600 - 400 - AirPassengers 200 - mamah 1950 1952 1954 1956 1958 1960 Time summary (AirPassengers) ## ## Min. 1st Qu. Median 10## [1] 1 We apply some transformations to the time series, and plot the results: AirPassengers %>% diff(lag = 12) %>% diff(laSeries: . 0.2- 0.1 - 0.0 ACF -0.1 - -0.2 - -0.3 - 18 24 12 Lag We fit a simple forecasting model to the AirPassengers data: f600 - AirPassengers 400 - 200 - понеделни 1 1960 1955 Time We finally check the residuals of the fitted simple forecasting moResiduals from Seasonal naive method 60 40- Why Mash wpoin mm 20- 0- . 1950 1952 1954 1956 1958 1960 0.75 - 30 - 0.50 - 20- AThe median number of international passengers in the AirPassengers time series was thousand

How many lag 1 differences are suggested for the seasonally differenced AirPassengers data?

The AirPassengers dataset is differenced at lag

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summary(AirPassengers) ## ## Min. 1st Qu. Median 104.0 180.0 265.5 Mean 3rd Qu. 280.3 360.5 Мах. 622.0

Median=265.5

diff(AirPassengers, lag 12)

Air passengers data is differenced at lag 12

0.2 - 0.1- 0.0. -0.1 - -0.2- 0.3 -

We see that only the first lag is significant. Hence only 1 lag 1 differences are suggested.

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