Use it and Excel to answer this question. It contains the United States Census Bureau’s estimates for World Population from 1950 to 2014. You will find a column of dates and a column of data on the World Population for these years. Generate the time variable t. Then run a regression with the Population data as a dependent variable and time as the dependent variable. Have Excel report the residuals.
(a) (4 marks) Based on the ANOVA table and t-statistics, does the regression appear significant?
(b) (10 marks) Calculate the Durbin-Watson Test statistic. Is there a serial correlation problem with the data? Explain. (d) (4 marks) What affect might your answer in part (b) have on your conclusions in part (a)?
Year | Population |
1950 | 2,557,628,654 |
1951 | 2,594,939,877 |
1952 | 2,636,772,306 |
1953 | 2,682,053,389 |
1954 | 2,730,228,104 |
1955 | 2,782,098,943 |
1956 | 2,835,299,673 |
1957 | 2,891,349,717 |
1958 | 2,948,137,248 |
1959 | 3,000,716,593 |
1960 | 3,043,001,508 |
1961 | 3,083,966,929 |
1962 | 3,140,093,217 |
1963 | 3,209,827,882 |
1964 | 3,281,201,306 |
1965 | 3,350,425,793 |
1966 | 3,420,677,923 |
1967 | 3,490,333,715 |
1968 | 3,562,313,822 |
1969 | 3,637,159,050 |
1970 | 3,712,697,742 |
1971 | 3,790,326,948 |
1972 | 3,866,568,653 |
1973 | 3,942,096,442 |
1974 | 4,016,608,813 |
1975 | 4,089,083,233 |
1976 | 4,160,185,010 |
1977 | 4,232,084,578 |
1978 | 4,304,105,753 |
1979 | 4,379,013,942 |
1980 | 4,451,362,735 |
1981 | 4,534,410,125 |
1982 | 4,614,566,561 |
1983 | 4,695,736,743 |
1984 | 4,774,569,391 |
1985 | 4,856,462,699 |
1986 | 4,940,571,232 |
1987 | 5,027,200,492 |
1988 | 5,114,557,167 |
1989 | 5,201,440,110 |
1990 | 5,288,955,934 |
1991 | 5,371,585,922 |
1992 | 5,456,136,278 |
1993 | 5,538,268,316 |
1994 | 5,618,682,132 |
1995 | 5,699,202,985 |
1996 | 5,779,440,593 |
1997 | 5,857,972,543 |
1998 | 5,935,213,248 |
1999 | 6,012,074,922 |
2000 | 6,088,571,383 |
2001 | 6,165,219,247 |
2002 | 6,242,016,348 |
2003 | 6,318,590,956 |
2004 | 6,395,699,509 |
2005 | 6,473,044,732 |
2006 | 6,551,263,534 |
2007 | 6,629,913,759 |
2008 | 6,709,049,780 |
2009 | 6,788,214,394 |
2010 | 6,858,584,755 |
2011 | 6,935,999,491 |
2012 | 7,013,871,313 |
2013 | 7,092,128,094 |
2014 | 7,169,968,185 |
a)
The regression equation is defined as,
Where the dependent variable Y = Population and independent variable t = year
Now, the regression analysis is done in excel by following steps
Step 1: Write the data values in excel. The screenshot is shown below,
(assign the t = 0 for year 1950)
Step 2: DATA > Data Analysis > Regression > OK. The screenshot is shown below,
Step 3: Select Input Y Range: 'Hours' column, Input X Range: 'Feet and Large' column then OK. The screenshot is shown below, (Click on Residual and Residual plot for residual analysis)
The result is obtained. The screenshot is shown below,
Conclusion:
Overall Significance
From the regression output summary (ANOVA table)
Significance F | |
Regression | 2.28529E-79 |
The significance F value is 2.28529E-79 which is greater than 0.05 at a 5% significance level which means the model fits the data value at the 5% significance level. Hence we can conclude that the independent variable year fits the model significantly.
Significance of Independent variable
From the regression output summary (t table)
P-value | |
Year | 2.28529E-79 |
The P-value for the independent variable is less than 0.05 at a 5% significance level hence we can conclude that independent variable is not significant in the model.
b)
The Durbin Watson test statistic is obtained using the formula,
Where N = 64, Yi is the current year's observation value and Yi-1 is the previous year's observation value.
From the data values,
From the data values,
The Durwin Watson statistic between 0 to 2 shows positive autocorrelation.
Consequences of positive autocorrelation (serial correlation)
The estimate of the standard error of estimate in the regression analysis is wrong, such that the model underestimates (less than) the true value of the standard error of the estimate.
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