Question

Suppose the rms voltage is 110 V in a single-loop circuit that contains a resistor R= 22 Ω. What is the average power dissipated by the resistor in this circuit?

Answer 1

the power dissipated in a purely resistive load fed from an AC rms supply is the same as that for a resistor connected to a DC supply and is given as:

$P = V_{rms} \times I_{rms} = I^2_{rms}R=\frac{V^2_{rms}}{R}$

So,

$P = \frac{V^2_{rms}}{R}=\frac{110^2}{22} W$

$P =550 W$