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The lowest excited state of a sodium atom lies at an energy of 3.371 x 10−19...

The lowest excited state of a sodium atom lies at an energy of 3.371 x 10−19 J/atom above the ground state. The degeneracy of the excited state is 2, whereas that of the ground state is 1. Calculate the fraction of sodium atoms in the excited state in an air-acetylene flame at 2600K.

Please show work I want to know the equation better I'm stuck on three different answers

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Answer #1

BE/KT e de Ne No NUmber o baticle in excitid state Ne Pasticle No = state rcound the exciled the genetacy Değinurauj state ho

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