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1. For calculating the pH of 0.01010 M KH PO., which of the following strategies is...
1) A solution of a weak monoprotic acid of unknown concentration was titrated with 0.23 M...
1) A solution of a weak monoprotic acid of unknown concentration was titrated with 0.23 M NaOH. If a 100.-mL sample of the acid solution required exactly 10. mL of the NaOH solution to reach the equivalence point, what was the original concentration of the weak acid? 2) During the titration on problem (2B), after 5.0 mL of NaOH addition, the pH = 3.68. What is the Ka of the weak acid? please show steps i have an exam tomorrow
thank you In the lecture we used titration of sodium carbonate with hydrochloric acid as an example to explain how t...
thank you
In the lecture we used titration of sodium carbonate with hydrochloric acid as an example to explain how to titrate a weak base with a strong acid. Suppose that you are using HNO3 to titrate Na3PO4, describe how to calculate pH at following different titration stages: (a) before titration (b) at 19 equivalence point (c) at 3rd equivalence point (d) between 2nd and 3rd equivalence points (e) after 3rd equivalence point Calculation is not required, simply write the...
Solve a, b and 2 1. Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. Fi...
Solve a, b and 2 1. Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. First what is the initial pH (before any NaOH is added)? The Ka for HOCl is 3.0 x 10-8 M. Answer is 3.96 a. What is the pH after 10.60 mL of NaOH are added? b. What is the pH after 15.30 mL of NaOH are added? 2. Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00 mL aqueous solution of 0.20 M H2A, where "H2A" is some arbitrary diprotic acid (Ka1 = 4.35 x 10-7, Kaz = 4.85 x 10-11 Estimate the pH values of the solution after the addition of 0.00, 10.00, 20.00, 30.00, 40.00, and 60.00 mL of 0.20 M NaOH. d) Calculation M4 - 30.00 ml NaOH Added: Here we realize that 20 ml...
ire anf eisures are complete 1. Caleulate the concentration (in M) of hydroxide ions in a...
ire anf eisures are complete 1. Caleulate the concentration (in M) of hydroxide ions in a solution at 25.0°C with a pOH of 4.223. D)599 x ǐo-19 E) 1.00 x 10- A)5.98 × 10-5 2. An aqueous solution C)1.67 x 104 will produce an acidic solution D) NHBr B) 1.67× 10-10 E) MgCl 12.0 pH of 100 solution 80 in flask 6.0 4.0 2.0 Equivalence Point 5 10 15 20 25 30 35 40 45 mL of 0.115 M NaOH...
1.) Calculate the pH of 1.0 L of the buffer 2.00 M CH3COONa/2.00 M CH2COOH before...
1.) Calculate the pH of 1.0 L of the buffer 2.00 M CH3COONa/2.00 M CH2COOH before and after the addition of 0.090 mol NaOH. The Ka of CH2COOH is 1.8 x 10% 2.) A 0.4277 g sample of a monoprotic acid neutralizes 244 ml of 0.1381 M KOH solution. Calculate the molar mass of the acid. 3.) In a titration experiment, 27.4 ml of 0.613 M HCOOH neutralize 21.5 ml of Ba(OH)2. What is the concentration of the Ba(OH)2 solution?
Following the Procedure of this experiment, a student titrated 0.653 g of an unknown weak, monoprotic...
Following the Procedure of this experiment, a student titrated 0.653 g of an unknown weak, monoprotic acid with 0.100 M NaOH and monitored the titration with a pH meter. His titration data were: Volume of NaOH solution added, mL /// pH 0.00 | 3.30 2.00 | 4.22 4.00 | 4.55 6.00 | 4.76 8.00 | 4.92 10.00 | 5.06 12.00 | 5.18 14.00 | 5.29 16.00 | 5.40 18.00 | 5.51 20.00 | 5.62 22.00 | 5.74 24.00 | 5.88...
1)A 25.0-mL sample of 0.130 M HCl is mixed with 15.0 mL of 0.240 M of...
1)A 25.0-mL sample of 0.130 M HCl is mixed with 15.0 mL of 0.240 M of NaOH. The pH of the resulting solution will be nearest [Suggestions: use an I-C-E table to solve this problem. Don't forget to use the TOTAL volume when calculating H+ (or OH-) concentration. 2)In the titration of 50.0 mL of 0.100 M benzoic acid (a monoprotic acid) with 50.0 mL of 0.100 M Na0H, the properties of the solution at the equivalence point will correspond...
Equivalence Point for Titration #1: 24.96 mL Equivalence Point for Titration #2: 25.40 mL Equivalence Point...
Equivalence Point for Titration #1: 24.96
mL
Equivalence Point for Titration #2: 25.40
mL
Equivalence Point for Titration #3: 25.20
mL
Midpoint pH for Titration #3: 9.80
QUESTIONS:
4) Set up the calculation required to determine
the concentration of the NaOH solution via titration of a given
amount of KHP. Include all numbers except the given mass of
KHP.
5) Set up the calculation required to determine
the concentration of the unknown strong acid via titration with a
known volume...
1. The pH of a 50.0 mL solution of 0.500 M HSCN (the analyte) was measured...
1. The pH of a 50.0 mL solution of 0.500 M HSCN (the analyte) was measured and found to be 3.80. What is pKa for the acid based on this measurement? 2. Trace amounts of an Indicator HIn was added to the solution described above. The indicator has a pKa (pkIn) of 11.85. This indicator is known to be yellow in solution in the form HIn and blue in solution in the form In- . In a forward titration, a...
thank you
In the lecture we used titration of sodium carbonate with hydrochloric acid as an example to explain how to titrate a weak base with a strong acid. Suppose that you are using HNO3 to titrate Na3PO4, describe how to calculate pH at following different titration stages: (a) before titration (b) at 19 equivalence point (c) at 3rd equivalence point (d) between 2nd and 3rd equivalence points (e) after 3rd equivalence point Calculation is not required, simply write the...
Part 4: Calculating pH values as a Titration Progresses - this is a tough question! Finally, consider a 20.00 mL aqueous solution of 0.20 M H2A, where "H2A" is some arbitrary diprotic acid (Ka1 = 4.35 x 10-7, Kaz = 4.85 x 10-11 Estimate the pH values of the solution after the addition of 0.00, 10.00, 20.00, 30.00, 40.00, and 60.00 mL of 0.20 M NaOH. d) Calculation M4 - 30.00 ml NaOH Added: Here we realize that 20 ml...
ire anf eisures are complete 1. Caleulate the concentration (in M) of hydroxide ions in a solution at 25.0°C with a pOH of 4.223. D)599 x ǐo-19 E) 1.00 x 10- A)5.98 × 10-5 2. An aqueous solution C)1.67 x 104 will produce an acidic solution D) NHBr B) 1.67× 10-10 E) MgCl 12.0 pH of 100 solution 80 in flask 6.0 4.0 2.0 Equivalence Point 5 10 15 20 25 30 35 40 45 mL of 0.115 M NaOH...
1.) Calculate the pH of 1.0 L of the buffer 2.00 M CH3COONa/2.00 M CH2COOH before and after the addition of 0.090 mol NaOH. The Ka of CH2COOH is 1.8 x 10% 2.) A 0.4277 g sample of a monoprotic acid neutralizes 244 ml of 0.1381 M KOH solution. Calculate the molar mass of the acid. 3.) In a titration experiment, 27.4 ml of 0.613 M HCOOH neutralize 21.5 ml of Ba(OH)2. What is the concentration of the Ba(OH)2 solution?
Equivalence Point for Titration #1: 24.96
mL
Equivalence Point for Titration #2: 25.40
mL
Equivalence Point for Titration #3: 25.20
mL
Midpoint pH for Titration #3: 9.80
QUESTIONS:
4) Set up the calculation required to determine
the concentration of the NaOH solution via titration of a given
amount of KHP. Include all numbers except the given mass of
KHP.
5) Set up the calculation required to determine
the concentration of the unknown strong acid via titration with a
known volume...
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