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In the lecture we used titration of sodium carbonate with hydrochloric acid as an example to explain how to titrate a weak ba

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Question 1.

(a) [H+] = (Kw*Ka3/[Na3PO4])1/2, pH = -Log[H+]

(b) [H+] = (Ka2*Ka3)1/2, pH = -Log[H+]

(c) [H+] = ([H3PO4]*Ka1)1/2, pH = -Log[H+]

(d) [H+] = Ka1*[H3PO4]/[NaH2PO4], pH = -Log[H+]

(e) [H+]total = [H+]H3PO4+ [H+]HNO3, pH = -Log[H+]

Note: [H+]H3PO4= ([H3PO4]*Ka1)1/2; [H+]HNO3 = [HNO3]

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