At 90 °C pure water has a [H3O+] = 1 x 10–6. What is the value...

Question

Question

At 90 °C pure water has a [H₃O⁺] = 1 x 10^–6. What is the value of K_w at 90 °C?

a. 1 x 10^–6

b. 1 x 10^–14

c. 7 x 10^–14

d. 1 x 10^–12

Answer 1

Answer #1

We know - Kw = [H30*]*[OH] ; kw = ionic product of water Also know that - of pure water, [H30+] = [OH-] So, we got - Kw = [H3

Answer 2

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