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ce aYe reedyce sheu a second humb er)
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The number that comes of first should be anything, then we want it to be on next two throws , provided the other two throws are same. Or iit to be on next one throw provided the other three throws are different.

Probability : = (1/6)^2(1/5)^2 *6 + (1/6) *(1/5) ^3 *4 = 1/150 + 4/750 = 0.012

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