Question

A: It is desired to prepare 700 mL of 0.150 normal Ba(OH)₂for use in the reaction:

2 HCl + Ba(OH)_2-------BaCl₂+ 2 H₂O

How many grams of Ba(OH)₂are needed? ___ g

B: For the following reaction:

H₂S + 2 KOH--- K₂S + 2 H₂O

Calculate the normality of a solution that contains 3.80 grams of H₂S in 784 mL of solution. ___N  

Answer 1

kindly post different questions separately. please rate

2 HCl + Bacolla Bacl + 2H2O Volume of BaCOH = 700 mL = 0.7L ( 1000 mL = 11) concentration of BaoHl2 = 0.150 N equivalent of Bacolo = normality (N) X volume = 0,150 N Y 0.7L = 0.105 eq basicity cel Become - 2 moles of BalHl2 = or equivalent of BalOH)2 besicity 0.105 = 0.0525 mol moler mass of BO(OH)2 = man of BacoHh needed 171.34 g/mol moles y molar mass 0.0525 mol X 171.34 g/mol = 8.999 Answer.