1. For the following reaction:
H2CO3 + 2 NaOH → Na2CO3 + 2 H2O
Calculate the normality of a solution that contains 2.68 grams of H2CO3 in 830 mL of solution.
2. For the following reaction:
H2S + 2
NaOH → Na2S +
2 H2O
Calculate the normality of a solution that contains
2.27 grams of H2S in
802 mL of solution.
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
1. For the following reaction: H2CO3 + 2 NaOH → Na2CO3 + 2 H2O Calculate the...
For the following reaction: H2S + 2 KOH--- K2S + 2 H2O Calculate the normality of a solution that contains 3.80 grams of H2S in 784 mL of solution. ___N
A: It is desired to prepare 700 mL of 0.150 normal Ba(OH)2for use in the reaction: 2 HCl + Ba(OH)2-------BaCl2+ 2 H2O How many grams of Ba(OH)2are needed? ___ g B: For the following reaction: H2S + 2 KOH--- K2S + 2 H2O Calculate the normality of a solution that contains 3.80 grams of H2S in 784 mL of solution. ___N
A 2.500 grams sample of a mixture of sodium carbonate (Na2CO3) and sodium chloride (NaCl) is dissolved in 25.00 mL of 0.798 M HCl (hydrochloric acid). Some acid will remain after the treatment of the sample. If 28.7 mL of 0.108 M NaOH is required to titrate the excess HCI then how many moles of sodium carbonate were present in the original sample? Hint: The moles of Na2CO3 present is equal to one- half the number of H30* moles and...
For the following reaction: 2 HI + Ba(OH)2 =BaI2 + 2 H2O What is the equivalent mass of Ba(OH)2? Calculate the number of equivalents in 39.6 grams of Ba(OH)2 For the following reaction: H2S + 2 KOH=K2S + 2 H2O What is the equivalent mass of H2S? Calculate the number of equivalents in 35.9 grams of H2S For the following reaction: HCl + KOH =KCl + H2O What is the equivalent mass of KOH Calculate the number of equivalents in...
Sodium hydroxide reacts with carbon dioxide as follows: 2 NaOH(s) + CO2(g) Na2CO3(s) + H2O(1) If 3.70 mol NaOH and 2.00 mol CO2 are allowed to react, how many moles of the excess reactant remains? 0.15 mol CO2 O 0.30 mol NaOH O 1.70 NaOH 1.00 mol CO2 How much energy is required to change the temperature of 1.50 L of water from 25.0 °C to 100.0 °C? The specific heat capacity of water is 4.184 J/g.°C; density H2O =...
1. How many milliliters of 0.112 M Na2CO3 will completely react with 27.2 mL of 0.135 M HNO3 according to the reaction 2HNO3(aq) + Na2CO3(aq) → H2O(l) + CO2(g) + 2NaNO3(aq) Part B.) A 25.0-mL sample of HNO3 solution requires 35.7 mL of 0.108 M Na2CO3 to completely react with all of the HNO3 in the solution. What is the concentration of theHNO3 solution? Part C.)Consider the reaction HCl(aq) + NaOH(aq) → NaOH(aq) + H2O(l) How much 0.113 M NaOH...
As early as 1938, the use of NaOH was suggested as a means of removing CO2 from the cabin of a spacecraft according to the following reaction : NaOH+CO2 -> Na2CO3 + H2O. If the average human body discharges 925. 0 g of CO2 per day how many moles of NaOH are needed each day for eacch person in the spacecraft?
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO22H++Na2CO3⟶2Na++H2O+CO2 A volume of 25.76±0.05 mL25.76±0.05 mL of HNO3HNO3 solution was required for complete reaction with 0.9089±0.0007 g0.9089±0.0007 g of Na2CO3Na2CO3, (FM 105.988±0.001 g/mol105.988±0.001 g/mol). Find the molarity of the HNO3HNO3 solution and its absolute uncertainty. Note: Significant figures are graded for this problem. To avoid rounding errors, do not round your answers until the very end of your calculations.
4. Using the following reaction, H2SO4 (aq) + 2 NaOH (aq) → Na2SO4 (aq) + 2 H2O () calculate the molarity of the H2SO4 solution if 17.45 mL of NaOH was necessary to reach the endpoint of a titration. The molarity of the NaOH solution was 0.425 M and 26.30 mL of H2SO4 was added to the Erlenmeyer flask.
1. 100 ml of 0.05 M H2S + 50ml of 0.1 M NaOH 2. 200 ml of 0.1 M Na2CO3 + 100 ml of 0,365% HCl 3. 50ml of 0.1M Na3PO4 + 100ml of 0.05 M H2SO4 4. 80 ml of 0.01M HNO2 + 20ml of 0.05 M HNO3 5. 20 ml of 0.05 M H2C2O4 + 200 ml of 0.01 M KOH 6. 100 ml of 0.05 M H2S + 100 ml of 0.1 M NaOH 7. 50 ml...