1. 100 ml of 0.05 M H2S + 50ml of 0.1 M NaOH
2. 200 ml of 0.1 M Na2CO3 + 100 ml of 0,365% HCl
3. 50ml of 0.1M Na3PO4 + 100ml of 0.05 M H2SO4
4. 80 ml of 0.01M HNO2 + 20ml of 0.05 M HNO3
5. 20 ml of 0.05 M H2C2O4 + 200 ml of 0.01 M KOH
6. 100 ml of 0.05 M H2S + 100 ml of 0.1 M NaOH
7. 50 ml of 0.01 M NaOH + 50 ml of 0.02 M NH3
8.100 ml of 0.01 M NH3 + 10 ml of 0.365 % HCl
9. 100 ml of 0.2 M Na2CO3 + 100 ml of 0.5 % HCl
10. 100 ml of 0.05 M H2CO3 + 50 ml of 0.1 M NaOH
11. 50 ml of 0.1M Na3PO4 + 100 ml of 0.05 M HNO3
12. 20 ml of 0.025 M H2C2O4 + 100 ml of 0.01 M KOH
13. 100 ml of 0.01 M HCl + 10 ml of 0.5 % NH3
How to find pH of solutions
1.Ans :- 100 ml of 0.05 M H2S + 50 ml of 0.1 M NaOH :-
No. of moles of H2S = Molarity x Volume in L
= 0.05 M x 0.100 L
= 0.005 mol
Also,
No. of moles of NaOH = Molarity x Volume in L
= 0.1 M x 0.050 L
= 0.005 mol
ICE table is :
.............................H2S..................+....................NaOH ----------------------> NaHS .................+....................H2O
Initial....................0.005 mol................................0.005 mol.........................0.0 mol.......................................
Change...............-0.005 mol...............................-0.005 mol.........................+0.005 mol...................................
Final.....................0.0 mol.....................................0.0 mol...............................0.005 mol.........................................
Total volume = 100 mL + 50 mL = 150 mL = 0.150 L
Molar concentration of NaHS = No. of moles / Volume in L
= 0.005 mol / 0.150 L
= 0.0333 mol/L
Since, NaHS is a salt of strong base NaOH and weak acid H2S and its pH can be calculated by using the formula :
pH = 1/2[14 + pKa + log C]
pH = 1/2 [14 + 6.99 + log 0.033 ]
pH = 1/2 [14 + 6.99 - 1.48 ]
pH = 1/2 x 19.51
pH = 9.75
Therefore, pH = 9.75
2. 200 ml of 0.1 M Na2CO3 + 100 ml of 0,365% HCl 3. 50ml of 0.1M Na3PO4 + 100ml of 0.05 M H2SO4 4. 80 ml of 0.01M HNO2 + 20ml of 0.05 M HNO3 5. 20 ml of 0.05 M H2C2O4 + 200 ml of 0.01 M KOH 6. 100 ml of 0.05 M H2S + 100 ml of 0.1 M NaOH How to find pH of solutions
How to find pH if solutions: 50 ml of 0.1M Na3PO4 + 100 ml of 0.05 M HNO3 20 ml of 0.025 M H2C2O4 + 100 ml of 0.01 M KOH 100 ml of 0.01 M HCl + 10 ml of 0.5 % NH3
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