In the titration of 100 ml of a 0.1 M H3PO4 with 0.5 M NAOH, calculate...
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In the titration of 100 ml of a 0.1 M H3PO4 with 0.5 M NAOH,
calculate...
Solve a, b and 2 1. Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. Fi...
Solve a, b and 2 1. Calculate the pH during the titration of 10.00 mL of 0.400 M hypochlorous acid with 0.500 M NaOH. First what is the initial pH (before any NaOH is added)? The Ka for HOCl is 3.0 x 10-8 M. Answer is 3.96 a. What is the pH after 10.60 mL of NaOH are added? b. What is the pH after 15.30 mL of NaOH are added? 2. Chloropropionic acid, ClCH2CH2COOH is a weak monoprotic acid...
Consider the titration of 100.0 mL of 0.0200 M H3PO4 with 0.121 M NaOH. Calculate the...
Consider the titration of 100.0 mL of 0.0200 M H3PO4 with 0.121 M NaOH. Calculate the milliliters of base that must be added to reach the first, second, and third equivalence points.
Calculate the concentrations of NaOH and maleic acid. 100 mL of 0.1 M NaOH was transferred...
Calculate the concentrations of NaOH and maleic acid. 100 mL of 0.1 M NaOH was transferred into a buret. 0.433 g of maleic acid was dissolved in a 100 mL volumetric flask. 25 mL of this solution was transferred into a plastic beaker, and 50 mL of distilled water was added. 6 mL of NaOH was added to get to the first equivalence point (brought pH to 1.99), and a total of 30 mL was added to reach the second...
a) Calculate the pH of a titration of 100 mL 1.5M HCl with 1.25M NaOH at...
a) Calculate the pH of a titration of 100 mL 1.5M HCl with 1.25M NaOH at equivalence. WHY is the pH what it is (if it’s 7, why is the solution neutral? If not 7, why?) b) Calculate the pH of a titration of 100 mL 1.5M HCOOH (Ka = 1.8 x 10-4) when 75 mL 1.25M NaOH has been added. c) What volume of 1.25M NaOH must be added to 100 mL of 1.5M HCOOH to reach equivalence?
Consider the titration of 43.4 mL of 0.265 M HF with 0.195 M NaOH. Calculate the...
Consider the titration of 43.4 mL of 0.265 M HF with 0.195 M NaOH. Calculate the pH at each of the following points. a. How many milliliters of base are required to reach the equivalence point? b Calculate the pH after the addition of 10.9 mL of base c. Calculate the pH at halfway to the equivalence point. d. Calculate the pH at the equivalence point. e. Calculate the pH after the addition of 86.8 mL of base.
a student was conducting a titration La=1.8•10^-5 48.92 mL of a 0.1089 M solution of acetic...
a student was conducting a titration
La=1.8•10^-5
48.92 mL of a 0.1089 M solution of acetic acid to a 200 ml beaker. The student then added 3 ant then added 35.8 mL of deionized water. After adding the water to the solution, the mixture was stirred to ensure proper mixing of solution Calculate the theoretical phat the following points of calibration curve. a) Initial pl, before addition of any NaOH? Be sure to consider the change in volume due to...
1.Determine the pH during the titration of 36.6 mL of 0.304 M ethylamine (C2H5NH2 , Kb...
1.Determine the pH during the titration of 36.6 mL of 0.304 M ethylamine (C2H5NH2 , Kb = 4.3×10-4) by 0.304 M HI at the following points. (a) Before the addition of any HI (b) After the addition of 16.1 mL of HI (c) At the titration midpoint (d) At the equivalence point (e) After adding 51.2 mL of HI b.Determine the pH during the titration of 61.4 mL of 0.450 M nitrous acid (Ka = 4.5×10-4) by 0.450 M NaOH...
(1) Determine the pH during the titration of 58.4 mL of 0.386 M hypochlorous acid (Ka...
(1) Determine the pH during the titration of 58.4 mL of 0.386 M hypochlorous acid (Ka = 3.5×10-8) by 0.386 M NaOH at the following points. (a) Before the addition of any NaOH (b) After the addition of 15.0 mL of NaOH (c) At the half-equivalence point (the titration midpoint) (d) At the equivalence point (e) After the addition of 87.6 mL of NaOH (2) Determine the pH during the titration of 39.1 mL of 0.369 M ethylamine (C2H5NH2 ,...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5. base Henderson-Hasselbalch equation: pH = pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is (Select) equivalence point on the titration curve. 2) The...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5 Henderson-Hasselbalch equation: pH =pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is before the equivalence point on the titration curve. 2) The pH...
a student was conducting a titration
La=1.8•10^-5
48.92 mL of a 0.1089 M solution of acetic acid to a 200 ml beaker. The student then added 3 ant then added 35.8 mL of deionized water. After adding the water to the solution, the mixture was stirred to ensure proper mixing of solution Calculate the theoretical phat the following points of calibration curve. a) Initial pl, before addition of any NaOH? Be sure to consider the change in volume due to...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5. base Henderson-Hasselbalch equation: pH = pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is (Select) equivalence point on the titration curve. 2) The...
A 10.0 mL sample of 0.75 M CH3CH2COOH(aq) is titrated with 0.30 M NaOH(aq) (adding NaOH to CH3CH2COOH). Determine which region on the titration curve the mixture produced is in, and the pH of the mixture at each volume of added base. K of CH3CH2COOH is 1.3 x 10-5 Henderson-Hasselbalch equation: pH =pK+ log NaOH CH3CH2COOH Parta): 1) After adding 18.0 mL of the NaOH solution, the mixture is before the equivalence point on the titration curve. 2) The pH...
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