mass of K2Cr2O7 = 1.70 mg = 0.0017 g
moles of K2Cr2O7 = 0.0017 mg / (294.19 g/mol) = 5.78*10^-6 mol
From the balanced equation:
Potassium dichromate and ethanol(C2H5OH) are in a 2:3 mole ratio.
moles of ethanol = 5.78*10^-6 mol*(3/2) = 8.67*10^-6 moles of ethanol
mass of ethanol = 8.67*10^-6 mol*(46.07 g/mol)
= 0.000399 g ethanol
= 0.399 mg ethanol
Blood alcohol content is usually measured in units of grams of alcohol per 100 mL of blood, multiplied by 100%.
Blood alcohol content = (mass of alcohol/volume of sample)*100
= (0.399/100)*100
= 0.399%
how can I determine the Blood alcohol content with this information? Course Contents Prelab Questions Determination...
i still need help on the last question. i tried equations but i keep getting it wrong. thank you i believe it's moles over volume and the answer should be a percentage Print Info The chemical method of analysis in determination of the blood alcohol content (%BAC) is: K2Cr207 + H2SO4 + C2H5OH Cr2(SO4)3 + K2SO4 + CH3COOH + H20 What are the stoichiometric coefficients for the reaction above? (please enter the coefficients without spaces and with a coma between...