Question

1. Consider the following data for aluminum, Cu, and an unknown metal Z. metal Z 10. Metal Mass (8) Specific heat (J/8°C) Initial temperature (°C) Final temperature (Al/Cu) Final temperature (AI/2) 10.0 0.900 40.00 51.25 48.50 CU 30.0 0.385 60.00 51.25 55.00 48.50 a) When Al and Cu are placed in contact with each other, the final temperature of the metals is 51.2°C. How much heat is exchanged between the two metals? q = MCST 9 = (10)%0.900/°C) 61.25-40) - (0)10.2005/°C)(11-25°C) = 101.25 I heat exchanged b) When Al and the unknown metal Z are in contact with each other, the final temperature is 48.5°C. Without doing the calculation, what can you predict about the specific heat capacity of the metal Z? Explain briefly but clearly. The temperature Change for Al is higher than temperature change for 2, therefore the specific heat for 2 is predicted to be higher than Al c) Now calculate the specific heat capacity of the unknown metal, Z. (include units!!)
Just 1c, cant figure out how to calculate specific heat without the heat energy

Answer 1

Heat exchanged between 2 metals must be same so as the final temperature is acheived 48.5 C

Z initial temperature 55 C Al inital temperature 40 C

So Z releases heat and Al accepts it.

So for Al / Z combination Heat taken up by Al = m*C_Al*$\Delta$T = 10gm* (0.900 J/gm*C) * (48.5-40) C = 76.5 J

So Z takes up 76.5 J heat

We can write m*C_Z*$\Delta$T = 10gm* (C_z)* (55-48.5) C = 76.5 J

So C _z = 1.17 J/gm*C