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The same amount of energy in the form of heat is added to a 2.00 g strip of each of the following metals. Each piece is initi
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Answer #1

1. The specific cheat capacity is given as = stehen m . c . – Te- m.c » A Tz = a X m . c Here, q= cheat absorbed 1,= initial8 and thence smaller would be the final temperature specific cheat capacity of he = 0.385 which is smallest among all melabs.

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