Ans 11 :
The heat lost by water will be gained by gold
Heat = mass of substance x specific heat x change in temperature
Let the final temperature be T
specific heat of water = 4.186 J/goC
12.0 x 4.186 x (57.0 - T) = 4.00 x 0.128 x (T - 18.2)
2863.224 - 50.232 T = 0.512 T - 9.3184
2863.224 + 9.3184 = 0.512 T + 50.232 T
2872.5424 = 50.744 T
T = 56.6
so the final temperature of the water in calorimeter will be 56.6oC
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