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5. What is the pH for a base if the concentration is 0.0045 M and Kb = 2.3 * 10-7? 6. What is the pH of 0.59 M NaNO2 if the K

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Answer #1

B-OH = BP + oH @ 0 0.0045 initial equilibrium X 0.0045- 1 Kb = [et] Ców] . (0,0049-n] 2.3 x10 7 = x² - (0,0048 x) rox10 - 2.

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