Answer:-
This question is solved by using the simple concept of chemical equilibrium and the effect on equilibrium on the equilibrium factors.
The answer is given in the image,
The chemical equation for calcium oxide and calcium carbonate equilibrium is described below: Cais - C0218)=...
3 pts Question 2 The chemical equation for calcium oxide and calcium carbonate equilibrium is described below. CaO + CO3(x)= CaCO3(9) AH° = -176 Predict how the following changes would shift the equilibria. Be sure to start by writing the equilibrium (K) equation Increased carbon dioxide concentration Choose ] equilibrium will shift to the left equilibrium will shift to the right equilibrium will be unaffected Increased partial pressure of carbon dioxic [Choose) One half of the calcium carbonate is removed...
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4. Consider the equilibrium in which solid calcium carbonate decomposes to the oxide plus carbon dioxide CaCO3(s) CaO(s) + CO2(g) Write down an expression for the equilibrium constant of this reaction in terms of the partial pressure of CO2. The standard enthalpies of formation of CaCO3(s), CO2(g) and CaO(s) are -1207.6 kJ mol", -393.5 kJ mol' and -634.9 kJ mol? respectively, and the standard entropies are 91.7JK'mol, 213.8JK' mol and 38.1 J K mol' (all at 298...
Cucurung an equilibrium constant from a heterogeneou! Calcium carbonate decomposes to form calcium oxide and carbon dioxide, like this: CaCO3(s) CaO(s)+ CO2(9) At a certain temperature, a chemist finds that a 6.5 L reaction vessel containing a mixture of calcium carbonate, calcium oxide, and carbon dioxide at equilibrium has the following composition: compound amount CaCO; 34.9 g Ca0 | 14,0 g CO2 39.28 Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant...
26. At room temperature, the decomposition of calcium carbonate into calcium oxide and carbon dioxide is highly unfavorable. At what temperature does the equilibrium become product-favored? CaCO3(s) = CaC(s) + CO2(g) AH° = = 177.8 kJ; ASⓇ = 160.5 mol mol
At 1073 K, the equilibrium pressure of carbon dioxide above mixtures of calcium carbonate and calcium oxide is 183 torr. (a) If 5.0 g of solid calcium carbonate is placed in a 4000- mL container at 1073 K, give the final amounts of the various species. CaCO3 = Caos DOO CO2 = (b) The same as (a), except 0.50 g of CaCO3 is placed in the container. CaCO3 = DO Ca0 = CO2 =
At high temperatures calcium carbonate decomposes into calcium oxide and carbon dioxide. CaCO3 (solid) {> Cao (solid) + CO2 (gas) Find the equilibrium pressure of this system at 1200 K if the equilibrium constant at 1400 K is 26. If the AGº of CaO(solid) and CaCO3 (solid) at 298 Kare -604 and -1128.8 kJ/mol respectively, estimate the equilibrium constant Kat 298 K and the equilibrium pressure. Discuss the effect of pressure on both the conversion of CaCO3 and the final...
QUESTION 3 Solid calcium carbonate (CaCO3) decomposes into solid calcium oxide (Cao) and carbon dioxide (CO) gas according to the following heterogeneous equilibrium: CaCO3(s) = Cao(s) + CO2(g) What is the correct equilibrium constant expression for this equation? OK (CaCO3] [Cao][CO2] ok, = [Coz] [Cao][CO.” [CaCO3] okea 0K = [Cao][CO2] [Ca][CO] (CaCO3] ok
q6
Choose the correct, balanced chemical equation for the following decomposition reaction: solid lithium carbonate decomposes with heat to form solid lithium oxide and carbon dioxide gas Li2CO3(s) bheatrxn Li2O(s) + CO2(g) • LiCO3(s) bheatrxn 2 LIO(s) + CO2(g) LICOz(s) wheatrxn Li(s) + CO2(g)
CaCO3(s) = Cao (s)+CO2 (g) When heated strongly, solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas, as represented by the equation above. A 2.0 mol sample of CaCO3(s) is placed in a rigid 100. L reaction vessel from which all the air has been evacuated. The vessel is heated to 898°C at which time the pressure of CO2(g) in the vessel is constant at 1.00 atm, while some CaCO3(s) remains in the vessel. a. Calculate...
pages 2-4 please! its equilibrium worksheet
2. A sample of gaseous BrCl is allowed to decompose in a closed container at 25C according to the equation below: 2BrCl(g) Bra(g) + Cl2(g) When the reaction reaches equilibrium, the following concentrations were obtained: [BrCl] = 0.38 M, [Cl:] = 0.26 M & [Br2] = 0.26 M. Determine the equilibrium constant for the reaction 3. A mixture of gases NOCI, Cl and NO was allowed to reach equilibrium at a particular temperature. The...